The coefficient of y in the expansion of (y² + c/y)5 is
Given, binomial expression is (y² + c/y)5 Now, Tr+1 = 5Cr × (y²)5-r × (c/y)r = 5Cr × y10-3r × Cr Now, 10 – 3r = 1 ⇒ 3r = 9 ⇒ r = 3 So, the coefficient of y = 5C3 × c³ = 10c³
(1.1)10000 is _____ 1000
Given, (1.1)10000 = (1 + 0.1)10000 10000C0 + 10000C1 × (0.1) + 10000C2 ×(0.1)² + other +ve terms = 1 + 10000×(0.1) + other +ve terms = 1 + 1000 + other +ve terms > 1000 So, (1.1)10000 is greater than 1000
The fourth term in the expansion (x – 2y)12 is
th term in (x – 2y)12 = T4 = T3+1 = 12C3 (x)12-3 ×(-2y)³ = 12C3 x9 ×(-8y³) = {(12×11×10)/(3×2×1)} × x9 ×(-8y³) = -(2×11×10×8) × x9 × y³ = -1760 x9 × y³
If n is a positive integer, then (√3+1)2n+1 + (√3−1)2n+1 is
Since n is a positive integer, assume n = 1 (√3+1)³ + (√3−1)³ = {3√3 + 1 + 3√3(√3 + 1)} + {3√3 – 1 – 3√3(√3 – 1)} = 3√3 + 1 + 9 + 3√3 + 3√3 – 1 – 9 + 3√3 = 12√3, which is an irrational number.
If the third term in the binomial expansion of (1 + x)m is (-1/8)x² then the rational value of m is
(1 + x)m = 1 + mx + {m(m – 1)/2}x² + …….. Now, {m(m – 1)/2}x² = (-1/8)x² ⇒ m(m – 1)/2 = -1/8 ⇒ 4m² – 4m = -1 ⇒ 4m² – 4m + 1 = 0 ⇒ (2m – 1)² = 0 ⇒ 2m – 1 = 0 ⇒ m = 1/2